ai giỏi hóa vào giúp em với ạ :3

` 1. `

` a. `

` CTHH : Ba_x(PO_4)_y `

Theo quy tắc : ` II.x = III.y `

` => x/y = (III)/(II) = 3/2 `

` => x = 3, y = 2 `

`CTHH : Ba_3(PO_4)_2 `

` KLNT = 137.3 + 31.2+16.2 = 601` amu` 

` b. ` 

` CTHH : N_xCl_y `

Theo quy tắc : ` III.x = I.y `

` => x/y = I/(III) = 1/3 `

` => x = 1, y = 3 `

`CTHH : NCl_3 `

` KLNT = 14 + 35,5.3 = 120,5 `amu `

` c, `

` CTHH : Cu_xCl_y `

Theo quy tắc : ` II.x = II.y `

` => x/y = I/(II) = 1/2 `

` => x = 1 , y = 2 `

`CTHH : CuCl_2 `

` KLNT = 64 + 35,5 . 2 = 135 `amu `

` d, ` 

` CTHH : S_xO_y `

Theo quy tắc : `VI.x = II.y `

` => x/y = (II)/(VI) = 2/6 =1/3`

` => x = 1, y = 3 `

`CTHH : SO_3`

` KLNT = 32 + 16 . 3 = 80 ` amu ` 

` e, `

` CTHH : N_xO_y `

Theo quy tắc : ` V.x = II.y `

` => x/y = (II)/V = 2/5 `

` => x = 2, y = 5 `

`CTHH : N_2O_5 `

` KLNT = 14 . 2 + 16. 5 = 108 `amu ` 

` g, `

` CTHH : Zn_x(OH)_y `

Theo quy tắc : `II.x = I.y `

` => x/y = I/(II) = 1/2 `

` => x = 1, y = 2 `

`CTHH : Zn(OH)_2 `

` KLNT = 65 + 16.2 + 1.2 = 99 `amu `

` h, `

` CTHH : Al_x(SO_4)_y `

Theo quy tắc : ` III.x = II.y `

` => x/y = (II)/(III) = 2/3 `

` => x = 2, y = 3 `

`CTHH : Al_2(SO_4)_3 `

` KLNT = 27.2 + 32 . 3 + 16.12 = 342 `amu `

` i, `

` CTHH : Mg_xS_y `

Theo quy tắc : ` II.x = II.y `

` => x/y = (II)/(II) = 2/2=1/1 `

` => x = 1, y = 1 `

`CTHH : MgS `

` KLNT = 24 + 32 =56 `amu`

` k, `

` CTHH : Fe_xO_y `

Theo quy tắc : ` III.x = II.y `

` => x/y = (II)/(III) = 2/3 `

` => x = 2, y = 3 `

`CTHH : Fe_2O_3 `

` KLNT = 56.2+16.3=160 `amu `